139 lines
3.5 KiB
R
139 lines
3.5 KiB
R
##
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# Libary imports
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##
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library(readODS)
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library(tidyverse)
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library(dplyr)
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library(leaflet)
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##
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# parse the input data, declare global values and auxiliary data
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##
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# read a data frame from the ods document
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df <- read_ods(path = "data/ironwood_data_cleaned.ods",
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sheet = 1)
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# site base location (to zero in the map)
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population_lat <- "-33.943917"
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population_lon <- "23.507389"
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# vector of condition names corresponding to the health index numbers
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condition_names <- c("healthy", "light damage",
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"medium damage", "severe damage",
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"at point of death")
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# colors for each condition
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condition_colors <- c("green", "yellow", "orange", "red", "black")
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##
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# 1.) asses the tree health of the entire population
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# create an overview of the populations health
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##
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# Calculate the percentage of trees in each health condition
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percentage <- proportions(table(df$tree_health_index)) * 100
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# Now, let's create the bar plot
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barplot(percentage,
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names.arg = condition_names,
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main = "Overview of Tree Health Index",
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xlab = "Health Index",
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ylab = "Percentage of Trees",
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ylim = c(0, max(percentage) + 10),
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col = condition_colors,
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border = "black")
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# Adding a legend
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legend("topright",
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legend = condition_names,
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fill = condition_colors)
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# Adding a box around the plot
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#box()
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# Add labels with the percentage of trees in each bar
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text(x = barplot(percentage, plot = FALSE),
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y = percentage,
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labels = paste0(round(percentage, 1), "%"),
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pos = 3)
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##
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# 2. Create a stacked barchart that represents all site and their health data
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##
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# Create data
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set.seed(1124)
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# for each site i need a table like this:
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#table(df$tree_health_index[1:14])
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colnames(health_data) <- paste("Site", seq(1,20), sep=" ")
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rownames(health_data) <- condition_names
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# create color palette:
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library(RColorBrewer)
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coul <- brewer.pal(3, "Pastel2")
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# Transform this data in %
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data_percentage <- apply(data, 2, function(x){x*100/sum(x,na.rm=T)})
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# Make a stacked barplot--> it will be in %!
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barplot(df$tree_health_index, col=coul , border="white", xlab="group")
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##
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# 3. perform a shapiro-wilk normality test
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# - the goal is to see if the health is normally distributed
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##
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# Perform Shapiro-Wilk test
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shapiro_test <- shapiro.test(df$tree_health_index)
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# Print the test results
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print(shapiro_test)
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# Check the p-value
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p_value <- shapiro_test$p.value
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# Interpret the results
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if (p_value < 0.05) {
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print("The data is not normally distributed (reject the null hypothesis)")
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} else {
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print("The data is normally distributed (fail to reject the null hypothesis)")
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}
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##
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# 4. try to fit health and location data in one plot
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##
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# create a subset of the site locations
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sites <- df[complete.cases(df$site_num),]
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# ensure all coordinates are numeric
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sites$site_lat <- as.numeric(sites$site_lat)
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sites$site_lon <- as.numeric(sites$site_lon)
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# create a map from our base location
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map <- leaflet() %>%
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setView(lng = population_lon,
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lat = population_lat,
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zoom = 16) %>%
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addTiles() %>%
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addCircleMarkers(
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data = df,
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lng = ~tree_lon,
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lat = ~tree_lat,
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radius = 2,
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color = ~condition_colors[tree_health_index+1],
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opacity = 1,
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fillOpacity = 1
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) %>%
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addCircleMarkers(
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data = sites,
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lng = ~site_lon,
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lat = ~site_lat,
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radius = 25,
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fill = FALSE,
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color = "green",
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opacity = 0.1
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)
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# show map
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map
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##
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# ToDo Tasks:
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##
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# 4. calculate the average DBH and try to correlate it with the health index
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# 5. plot health indices of each site on a map and try to find patterns |