add solution to part b
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@@ -3,9 +3,9 @@ import string
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from aocd.models import Puzzle
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from aocd import submit
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def eval_priority(rucksack: str) -> int:
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def eval_item_priority(rucksack: str) -> int:
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'''
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evaluates the priority of a duplicate item
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evaluates the priority of a common item
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'''
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# create a map of priority values
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@@ -15,13 +15,28 @@ def eval_priority(rucksack: str) -> int:
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size = len(rucksack)
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a,b = rucksack[:size//2], rucksack[size//2:]
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# find the duplicate item
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duplicate = ''.join(
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# find the common item
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common = ''.join(
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set(a).intersection(b)
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)
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# return the priority
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return priorities[duplicate]
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return priorities[common]
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def eval_badge_priority(rucksacks: list) -> int:
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'''
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evaluate the priority of duplicate items over groups of three rucksacks
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'''
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# create a map of priority values
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priorities = dict(zip(string.ascii_letters, range(1,53)))
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# find common item among three sets
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common = ''.join(
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set(rucksacks[0]) & set(rucksacks[1]) & set(rucksacks[2])
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)
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return priorities[common]
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def parse_input(data: list) -> list:
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'''
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@@ -35,10 +50,14 @@ if __name__ == "__main__":
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puzzle = Puzzle(year=2022, day=3)
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supplies = parse_input(puzzle.input_data)
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# part a: determine the priority of all duplicate items
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answer = sum([eval_priority(rucksack) for rucksack in supplies])
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print(f'sum of priorities of all duplicate items: {answer}')
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submit(answer, part='a', day=3, year=2022)
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# part a: determine the priority of dupplicate items in compartments
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answer_a = sum([eval_item_priority(rucksack) for rucksack in supplies])
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print(f'sum of priorities of all common items amongst compartments: {answer_a}')
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submit(answer_a, part='a', day=3, year=2022)
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# part b:
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#submit(total, part='b', day=3, year=2022)
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# part b: determine the priority of common items in groups of three
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# split the supply list into groups of three
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rucksacks = [ supplies[i:i+3] for i in range(0,len(supplies),3) ]
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answer_b = sum([ eval_badge_priority(rucksack) for rucksack in rucksacks ])
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print(f'sum of priorities of all common items amongst groups of three: {answer_b}')
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submit(answer_b, part='b', day=3, year=2022)
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